What is the derivative of: y=1/(x+1)+2?
That derivative is - 1 / (x + 1)²
\(y=\frac{1}{x+1}+2=(x+1)^{-1}+2\\\\y'=\left[(x+1)^{-1}+2\right]'=-(x+1)^{-1-1}=-(x+1)^{-2}=-\frac{1}{(x+1)^2}\)
