The pH of a solution decreases by 2.0. How does the hydronium ion concentration of the solution change?


increases to 2 times the original concentration

increases to 100 times the original concentration

decreases to 1/100 of the original concentration

decreases to 1/2 of the original concentration

Verified Answer :

Answer: The correct answer is 'increases to 100 times the original concentration'.

Explanation:

let the initial pH be x

The original concentration of \([H^+]\) initially present be y

\(x=-log[y]\)...(1)

Final concentration of \([H^+]\) when pH reduced by 2 be z

\(x-2=-log[z]\)...(2)

Putting the value of 'x' from (1) into (2) we get :

\(-log[y]-2=-log[z]\)

\(z=10^2y=100y\)

When pH of a solution decreases by 2.0, hydronium ion concentration of the solution increases to 100 times the original concentration



Answer:

B, is the answer