An above-ground swimming pool in the shape of a cylinder has a diameter of 18 feet and a height of 4.5 feet. If the pool is filled with water to 6 inches from the top of the pool, what is the volume, to the nearest cubic foot, of the water in the pool?⇆
The volume of a cylinder is
(pi) (radius²) (height) .
Radius = 1/2 diameter.
Radius of this pool = (1/2) (18 ft) = 9 ft
The pool is a cylinder with height of 4.5 feet.
The water in it is also a cylinder, but only 4 ft high.
Volume of the water =
(pi) x (radius²) x (height)
= (pi) x (9 ft)² x (4 ft)
= (pi) x (81 ft²) x (4 ft)
= (pi) x (324 ft³) = 1,017.9 ft³ .
Answer:
the correct answer is the V = 1144.53
Step-by-step explanation:
This is the answer because you use the formula V = πr^2h
And you get 1144.53