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One plane at 520 feet is ascending at a rate of 40 feet per minute, while another plane at 3800 feet is descending at a rate of 120 feet per minute. how long will it take the two lanes to be at the same altitude?

Verified Answer :

coolcat7

Plane A 520 feet vertical rise 40 feet/min
plane B 3800 feet vertical dip 120 feet per minute.
vertically the speeds are 40 feet / minute & 120 feet /minute.
120 + 40 = 160 feet per minute.
the distance between them = 3800 -520 =3280 feet
t= d/r
3280/160
t = 20.5 minutes. they will be at the same altitude. 

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