Mass of solute = 14,0 g
Molar mass ( NH4Br ) = 14 + 1 . 4 + 80 = 98 g/mol-1
volume of the solution = 150 mL = 0,15 L
Molarity of the solution = mol/L-1
\(M = \frac{m}{mm.V}\)
\(M = \frac{14,0}{98.0,15}\)
\(M = \frac{14,0}{14,7}\)
\(M = 0,952 mol/L ^{-1}\)
Hope this helps!
