Maximum rectangular area for
the painting that is allowed for the contest = 3003.04 cm^2
Width of Carmen's painting = 16 cm
Let us assume the maximum
Length of Carmen's painting that will be within the contest rules = x cm
We already know that
Area of a rectangle = Length of the rectangle Breadth of the rectangle
3003.04 = x 16
x = 3003.04/16 cm
= 187.69 cm
So the length of Carmen's painting should not be greater than 187.69 cm to be within the rules of the contest. I hope the procedure is clear enough for you to understand.