A cylinder has the circumfrence of 16\(\pi\) inches and its height is half the radius of the cylinder. What is the total surface area of the cylinder? Give your answer in terms of \(\pi\). Explain how you found your answer.

Verified Answer :

Leader

Circumference = 2\(\pi\)r
If the circumference of the base of the cylinder is 16\(\pi\) then
16\(\pi\) = 2\(\pi\)r
Divide by 2 on both sides.
8\(\pi\) = \(\pi\)r
Divide by \(\pi\) on both sides.
8=r

So our radius is 8. So the height of the cylinder is 8/2 = 4.

The surface area of a cylinder is
\(SA=2\pi rh+2\pi r^2\)

Just plug in r as 8 and h as 4.

\(SA=2\pi (8)(4)+2\pi (8)^2\)
\(SA=2\pi 32+2\pi 64\)
\(SA=64\pi + 128\pi\)
\(SA=192\pi\)

The surface area is \({\boxed{192\pi}\).