Answer: The mass of sodium chloride formed will be 58.5 g
Explanation:
To calculate the number of moles, we use the equation:
\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\) .....(1)
Given mass of sodium = 23 g
Molar mass of sodium = 23 g/mol
Putting values in equation 1, we get:
\(\text{Moles of sodium}=\frac{23g}{23g/mol}=1mol\)
Given mass of chlorine gas = 35.5 g
Molar mass of chlorine gas = 71 g/mol
Putting values in equation 1, we get:
\(\text{Moles of chlorine gas}=\frac{35.5g}{71g/mol}=0.5mol\)
The chemical reaction for the formation of sodium chloride follows the equation:
\(2Na+Cl_2\rightarrow 2NaCl\)
By stoichiometry of the reaction:
2 moles of sodium reacts with 1 mole of chlorine gas.
So, 1 mole of sodium will react with = \(\frac{1}{2}\times 1=0.5mol\) of chlorine gas.
Thus, the formation of sodium chloride can be calculated by using any of the reactant.
By stoichiometry of the reaction:
2 moles of sodium produces 2 moles of sodium chloride.
So, 1 mole of sodium will react with = \(\frac{2}{2}\times 1=1mol\) of sodium chloride.
Now, calculating the mass of sodium chloride by using equation 1, we get:
Moles of sodium chloride = 1 mole
Molar mass of sodium chloride = 58.5 g/mol
Putting values in equation 1, we get:
\(1mol=\frac{\text{Mass of NaCl}}{58.5g/mol}\\\\\text{Mass of NaCl}=58.5g\)
Hence, the mass of sodium chloride formed will be 58.5 g
