Answer:
1.325 moles of \(C_{4}F_{8}\) are in 265 g of \(C_{4}F_{8}\)
Explanation:
Number of moles of a compound=(mass of the compound)/(molar mass of the compound)
Molar mass of \(C_{4}F_{8}\) = \((4\times atomic mass of C)+(8\times atomic mass of F)\) or \((4\times 12g)+(8\times 19g)\) or 200 g.
So number of moles of \(C_{4}F_{8}\) in 265 g of \(C_{4}F_{8}\) is (265g/200g) or 1.325 moles
