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What is the probability of not drawing a green marble from a jar containing 7 red, 4 green, 3 white, and 9 blue marbles?

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iloveonedirection

\(7+4+3+9\)
\(11+12\)
\(23\)

\(\frac{23}{23} - \frac{4}{23}\)

\(\frac{23-4}{23}\)

\(\frac{19}{23}\) \(chance\)

Answer:

Probability of not drawing a green marble is 19/23.

Step-by-step explanation:

A jar is containing 7 red, 3 white, and 9 blue marbles.

Then the probability to draw a green marble will be = Numbers of green marbles/ Total numbers of marbles of all colors

P(G) = 4/(7 + 4 + 3 + 9)

P(G) = 4/23

Now the probability of not drawing a green marble = 1 - probability of drawing a green ball

P = 1 - 4/23 = 19/23

Therefore answer is 19/23.

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