Answered

A motorist driving at 25 meters/second decelerates to

15 meters/second. The combined mass of the vehicle and the driver is 1.5 × 10³ kilograms. What is the amount of mechanical work done by the vehicle?

A7.5 x 10^4 joules
B1.5 x 10^5 joules
C3.0 x 10^5 joules
D6.2 x 10^5 joules

Verified Answer :

pingwin09

Work done = 0.5m[(v2)^2 - (v1)^2]
where m is mass,
v2 and v1 are the velocities.

Given that m = 1.50 x 10^3 kg, v2 = -15 m/s (decelerates), v1 = 25 kg,

Work done = 0.5 1.50 x 10^3 ((-15)^2 - 25^2) = 3 x 10^5 joules

Just ignore the negative value for the final result because work is a scalar quantity.

Answer:

C.

3.0 × 10^5 joules

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