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To get from the post office to the library, Sindy walked due north and then due east. The distance Sindy walked east is 20 meters more than the distance she walked north. If Sindy were able to walk directly from the post office to the library in a straight line, she would have walked 150 meters. Suppose x represents the distance Sindy walked north. Which equation can be used to find x?

x^2+(x+20)^2=150^2

202=x^2-150^2

x+(x+20)=150

x^2+(x+150)^2=20^2

Verified Answer :

Sofiadecredico
Ax∧2+(x+20∧2=150∧2  is correct.

because you need to plug the numbers into the pathagoreum theorum which is 
a∧2+b∧2=c∧2

150 is our c because it is the side right accross from the right angle.

which number is a and which number is b does not matter.

x is the distance north so we can assign that to a and the distace east is north plus 20 so we can assign b to x+20.

Answer:

150 is our c because it is the side right accross from the right angle.

which number is a and which number is b does not matter.

x is the distance north so we can assign that to a and the distace east is north plus 20 so we can assign b to x+20.

a. x∧2+(x+20∧2=150∧2  is correct.

because you need to plug the numbers into the pathagoreum theorum which is 

a∧2+b∧2=c∧2

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