Answer:
One of the equivalent expressions is \(2(j+k)\).
Step-by-step explanation:
In the expression
\(j+j+2k\)
there are 2 \(j's\) ;therefore, the expression can be rewritten as
\(2j+2k\),
and using the reverse distribute property which says
\(ax+ay=a(x+y)\),
we rewrite our expression as
\(2j+2k = \boxed{2(j+k).}\)
