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Identify the arc length of TV in terms of π. (image is attached)


The answers for this question were:


≈0.67pi in., ≈1.83pi in., ≈3.67pi in., or ≈1.33pi in.

Identify the arc length of TV in terms of π. (image is attached) The answers for this question were: 0.67pi in., 1.83pi in., 3.67pi in., or 1.33pi in. class=

Verified Answer :

MJbrown

Answer:       ≈ 3.67π in.

Step-by-step explanation:

∠SMV and ∠VMT are supplementary. Therefore,  


m∠VMT = 180∘ − m∠SMV

It is given that m∠SMV = 48∘. Substitute the given value and simplify.


m∠VMT = 180∘ − 48∘

=132∘                                                                                                                  Arc length is the distance along an arc measured in linear units. The formula for Arc Length is L=  2πr (m∘/360∘).


The length of the radius is given as 5 in. Substitute the known values into the formula.


L= 2π (5) (132/360)

Simplify.


L= 33/9π

Round to the nearest tenth.  


L ≈ 3.67π in.

Therefore, the arc length of TV is ≈ 3.67π in.

The arc length of TV is ≈ 3.67π in.

What is Arc length?

Arc length is the distance between two points along a section of a curve.

Given:

∠SMV = 48 and MT= 5 in

As, ∠SMV and ∠VMT are forms linear pair. So,  

∠VMT + ∠SMV = 180∘

∠VMT= 180 -  ∠SMV

∠VMT = 180∘ − 48∘

∠VMT =132∘      

Now, length of arc will be,

= \(\theta\)/360 2πr

=132/3602π5

=132/36010π

=33/9π

≈ 3.67π in.

Hence, the arc length of TV is ≈ 3.67π in.

Learn more about Arc length here:

https://brainly.com/question/16403495

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