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aryn814
aryn814 aryn814
  • 04-01-2016
  • Mathematics
Answered

If f(x)=8sin^6x - cos^2x. Find f'(\(\pi /4\).

Verified Answer :

Billymkhoi
Billymkhoi Billymkhoi
  • 04-01-2016

f'(x) = 48(sin(x))^5cos(x)- 2cos(x)(-sin(x))
= 48(sin(x))^5cos(x)+ 2cos(x)sin(x)

f'(π/4)= 48(sin(π/4))^5*cos(π/4)+ 2cos(π/4)sin(π/4)=7.

The final answer is 7.

Hope this helps~

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