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Anonymous Anonymous
  • 23-07-2014
  • Mathematics
Answered

Solve by completing the square

x^2-2x-5=0

Verified Answer :

konrad509
konrad509 konrad509
  • 23-07-2014

\(x^2-2x-5=0 \\ x^2-2x+1-6=0\\ (x-1)^2=6\\ x-1=\sqrt6 \vee x-1=-\sqrt6\\ x=1+\sqrt6 \vee x=1-\sqrt6\)

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