Answer: 4) 40 ml
Solution :
According to the neutralization law,
\(M_1V_1=M_2V_2\)
where,
\(M_1\) = molarity of NaOH solution = 0.30 M
\(V_1\) = volume of NaOH solution = ?
\(M_2\) = molarity of HCl solution = 0.80 M
\(V_2\) = volume of HCl solution = 15 ml
Now put all the given values in the above law, we get the volume of NaOH solution.
\((0.30M)\times V_1=(0.80M)\times (15ml)\)
\(V_1=40ml\)
Therefore, the volume of 0.30 M NaOH required to neutralize 15 ml of 0.80 M HCl is 40 ml.
