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Answered

A 0.0600-kilogram ball traveling at 60.0 meters

per second hits a concrete wall. What speed

must a 0.0100-kilogram bullet have in order to

hit the wall with the same magnitude of

momentum as the ball?

(1) 3.60 m/s (3) 360. m/s

(2) 6.00 m/s (4) 600. m/s

Verified Answer :

The momentum of ball is given by:

\(\Delta Q=mv \\ \Delta Q=6*10^{-2}*60 \\ \Delta Q=3.6kg*m/s\)
  
     Since both have the same momentum, we have:

\(\Delta Q=MV \\ 3.6=10^{-2}V \\ \boxed {V=360m/s}\)

Number 3

If you notice any mistake in my english, please let me know, because i am not native.    

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