Answer: The correct answer is option 3.
Explanation: There are three types of particles that are emitted when a radioisotope undergo decay process:
1. Alpha particle: This particle is emitted when a radioisotope undergoes alpha decay process. The charge on the particle is +2 and mass number is 4.
\(_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha\)
2. Beta-particle: This particle is emitted when a radioisotope undergoes beta-minus decay process. The charge on the particle is -1 and mass number is 0.
\(_Z^A\textrm{X}\rightarrow _{Z+1}^{A}\textrm{Y}+_{-1}^0\beta\)
3. Positron particle: This particle is emitted when a radioisotope undergoes beta-plus decay process. The charge on the particle is +1 and mass number is 0.
\(_Z^A\textrm{X}\rightarrow _{Z-1}^{A}\textrm{Y}+_{+1}^0\beta\)
For the given options undergoing decay processes:
Option 1:
\(_1^3\textrm{H}\rightarrow _{2}^{3}\textrm{He}+_{-1}^0\beta\)
It emits beta-particle.
Option 2:
\(_7^{16}\textrm{N}\rightarrow _{8}^{16}\textrm{O}+_{-1}^0\beta\)
It emits beta-particle.
Option 3:
\(_{10}^{19}\textrm{Ne}\rightarrow _{9}^{19}\textrm{F}+_{+1}^0\beta\)
It emits positron-particle.
Option 4:
\(_{94}^{239}\textrm{Pu}\rightarrow _{92}^{235}\textrm{U}+_2^4\alpha\)
It emits alpha particle.
Hence, the correct option is Option 3.
