irrational equations 64^1/3 how to simplify?
For indicies, the numerator is the normal power, and the denominator is a root as such. So 1/2 would be square root, 1/3 would be cube root, 1/4 would be 4th root and so on.So, 64^(1/3) is the third root of 64, which is equal to 4.
my answer on pitcure :)
