A car, initially traveling at 15 meters per second

north, accelerates to 25 meters per second north

in 4.0 seconds. The magnitude of the average

acceleration is

(1) 2.5 m/s^2 (3) 10. m/s^2

(2) 6.3 m/s^2 (4) 20. m/s^2

Verified Answer :

The magnitude of the acceleration of the car is given by:
\(a= \frac{v_f-v_i}{t}\)
where
\(v_i=15 m/s\) is the initial speed of the car
\(v_f=25 m/s\) is the final speed of the car
\(t=4.0 s\) is the time it takes for the car to change its speed

Substituting these data into the formula, we find the magnitude of the average acceleration of the car:
\(a= \frac{25 m/s-15 m/s}{4.0 s}=2.5 m/s^2\)

therefore, the correct answer isĀ (1) 2.5 m/s^2.