Answered

How much total energy is dissipated in 10. seconds

in a 4.0-ohm resistor with a current of

0.50 ampere?

(1) 2.5 J (3) 10. J

(2) 5.0 J (4) 20. J

Verified Answer :

Answer : Total energy dissipated is 10 J

Explanation :

It is given that,

Time. t = 10 s

Resistance of the resistors, R = 4-ohm

Current, I = 0.5 A

Power used is given by :

\(P=\dfrac{E}{t}\)

Where

E is the energy dissipated.

So, E = P t.............(1)

Since, \(P=I^2R\)

So equation (1) becomes :

\(E=I^2Rt\)

\(E=(0.5\ A)^2\times 4\Omega \times 10\ s\)

\(E=10\ J\)

So, the correct option is (3)

Hence, this is the required solution.

Answer:

3) 10 J

Explanation:

Electrical energy dissipated is given as

\(U = i^2 R T\)

here we know that

i = electrical current = 0.50 A

R = 4 ohm

T = 10 s

so we have electrical energy given as

\(U = (0.50)^2(4)(10)\)

\(U = 10 J\)

Related Questions