kimeH4anzalexygirl
Answered

When Earth and the Moon are separated by a

distance of 3.84 × 10^8 meters, the magnitude of

the gravitational force of attraction between

them is 2.0 × 10^20 newtons. What would be the

magnitude of this gravitational force of attraction

if Earth and the Moon were separated by a

distance of 1.92 × 10^8 meters?

(1) 5.0 × 10^19 N (3) 4.0 × 10^20 N

(2) 2.0 × 10^20 N (4) 8.0 × 10^20 N

Verified Answer :

Using the Universal Gratitation Law, we have:

\(F= \frac{MmG}{d^2} \\ MmG=2*10^{20}*(3.84*10^8)^2 \\ MmG=29.4912*10^36\)
 
     Again applying the formula in the new situation, comes:

\(F= \frac{MmG}{d^2} \\ F= \frac{29.4912*10^36}{(1.92*10^8)^2} \\ \boxed {F=8*10^{20}}\)

Number 4

If you notice any mistake in my english, please let me know, because i am not native.

AL2006


The strength of the gravitational forces between two masses is
inversely proportional to the square of the distance between them.

So if you change the distance to

               (1.92 x 10⁸) / (3.84 x 10⁸)  =  1/2

of what it is now, then you would change the force to

                     1 / (1/2)²  =  4

of what it is now.

   (4) x (2 x 10²⁰)  =  8.0 x 10²⁰ newtons .