Answered

What volume of 0.500 M HNO3(aq) must completely react to neutralize 100.0 milliliters of 0.100 M KOH(aq)?

(1) 10.0 mL (3) 50.0 mL

(2) 20.0 mL (4) 500. mL

Verified Answer :

Billymkhoi

KOH+ HNO3--> KNO3+ H2O

From this balanced equation, we know that 1 mol
HNO3= 1 mol KOH (keep in mind this because it will be used later).


We also know that 0.100 M KOH aqueous
solution (soln)= 0.100 mol KOH/ 1 L of KOH soln (this one is based on the
definition of molarity).


First, we should find the mole of KOH:

100.0 mL KOH soln (1 L KOH soln/
1,000 mL KOH soln) (0.100 mol KOH/ 1L KOH soln)= 1.0010^(-2) mol KOH.


Now, let's find the volume of HNO3 soln:

1.0010^(-2) mol KOH (1 mol HNO3/ 1 mol KOH) (1 L HNO3 soln/ 0.500 mol HNO3)* (1,000 mL HNO3 soln/ 1 L HNO3 soln)= 20.0 mL HNO3 soln.


The final answer is (2) 20.0 mL.


Also, this problem can also be done by using
dimensional analysis. 

Hope this would help~

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