Simplify the expression (3x^2+4x-3)-(2x-1)
\((3x^2 + 4x - 3) - (2x - 1) \\ \\ 3x^2 + 4x - 3 - 2x + 1 \\ \\ 3x^2 + 4x - 3 - 2x + 1 \\ \\ 3x^2 + (4x - 2x) - 3 + 1 \\ \\ 3x^2 + 2x - 3 + 1 \\ \\ 3x^2 + 2x - 2 \\ \\ Answer: 3x^2 + 2x - 2\)
\((3x^2+4x-3)-(2x-1) = 3x^2 + 4x -3 -2x + 1\\\\ = 3x^2 + 4x -2x -3 + 1\\\\ = \boxed{3x^2 +2x -2}\)
