Verified Answer :

ameeki

Let the least number = n

Since they are consecutive even numbers, they must be two numbers apart each; (n+2) and (n+4) are the second and third consecutive numbers, respectively.

Now we must add them together, and set the equation equal to 66.
n + (n+2) + (n+4) = 66

Simplify this to be: 3n + 6 = 66
66-6 = 3n
60 = 3n
n = 20

This means that the least number is 20, the second number is 22, and the third number is 24. 

AL2006


If the three numbers were all equal, each one would be  1/3  of 66 .
That's  22, so the numbers would be  22,  22,  and 22 .

If you simply take  2  away from the first number and add it to
the last one, then their sum doesn't change, but now you have
20,  22,  and  24 .

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