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Anonymous Anonymous
  • 30-12-2015
  • Mathematics
Answered

Three consecutive multiples of 7 have a sum of 126.


What is the greatest number?

Verified Answer :

konrad509
konrad509 konrad509
  • 30-12-2015

\(7n+7n+7+7n+14=126\\ 21n+21=126\\ 21n=105\\ n=5\\\\ 7\cdot5+14=49\)

The greatest is 49.


\(2n+2n+2+2n+4=84\\ 6n+6=84\\ 6n=78\\ n=13\\\\ 2\cdot13=26\)

The least is 26.

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