First find the slope.
We know these two points are in the line: (0,8) and (6,5)
\(\sf Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{8-5}{0-6} = \frac{3}{-6} = \boxed{-\frac{1}{2}}\)
The slope is -1/2. The y-intercept can be found when x = 0. And we know that the point (0,8) is on the line and x = 0, therefore the y-intercept is 8.
Plugging this into the slope-intercept form which is
y = mx + b, where m is the slope and b is the y-intercept, we get:
y = (-1/2)x + 8
