Answer:
The area of the regular octagon having sides of 8 inches is 309 square inches.
Step-by-step explanation:
It is given that Length of each side of a regular octagon is 8 inches.
Now, the formula for finding the area of a regular octagon is:
\({\text}{Area}=2(1+\sqrt{2}){\times}(Side)^2\)
Substituting the given values, we get
\(A=2(1+1.414){\times}(8)^2\)
\(A=2(2.414){\times}64\)
\(A=308.99{in^2\)
\(A\)≈\(309 in^2\)
Thus, the area of the regular octagon having sides of 8 inches is 309 square inches.
