Find the area of the regular pentagon.
AREA OF A REGULAR PENTAGON EQUATION:A = 1/4 √5(5+2√5) a² ; a = sideA = 1/4 √5(5+2√5) 8²A = 1/4 √5(5+2(2.24) 64A = 1/4 √5(5+4.48) 64A = 1/4 √5(9.48 64A = 1/4 √47.4 64A = 1/4 6.88 64A = 1/4 * 440.32A = 110.08 cm²