Verified Answer :

Soham

i) \(2 ^{a}*2 ^{b}* 2^{c}\)          
We know that \(x^{a} * x^{b} = x^{a+b}\)
Therefore, 
\(2 ^{a}*2 ^{b}* 2^{c}\) = \(2 ^{a+b+c}\)
ii) \(2 ^{a+b} * 2 ^{a-b}= 2^{(a+b+a-b)}\)
\(= 2^{2a}\)