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Gracelux
Gracelux Gracelux
  • 18-07-2014
  • Mathematics
Answered

Find all zeros (both real and complex) for the function f(x)=x^3-5x^2+4x+10

Verified Answer :

konrad509
konrad509 konrad509
  • 18-07-2014

\(f(x)=x^3-5x^2+4x+10\\ f(x)=x^3+x^2-6x^2-6x+10x+10\\ f(x)=x^2(x+1)-6x(x+1)+10(x+1)\\ f(x)=(x+1)(x^2-6x+10)\\\\ x+1=0\\ x=-1\\\\ x^2-6x+10=0\\ x^2-6x+9+1=0\\ (x-3)^2=-1\\ x-3=i \vee x-3=-i\\ x=3+i \vee x=3-i\\\\ x=\{-1,3-i,3+i\}\)

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