1 / ( r + 3 ) = ( r + 4 ) / ( r - 2 ) + 6 / ( r - 2 ); where r isn't -3 and 2;
1 / ( r + 3 ) = ( r + 10 ) / ( r - 2 )
r - 2 = ( r + 10 )( r + 3)
r - 2 = r ^2 + 13r + 30
r^2 + 12 r + 32 = 0
r^2 + 4r + 8r + 32 = 0
r( r + 4 ) + 8( r + 4 ) = 0
( r + 4 )( r + 8 ) = 0
r + 4 = 0 => r = - 4;
or
r + 8 = 0 => r = - 8;
The solutions are : -4 ; -8.
