Let
x------> the length of the rectangle
y------> the width of the rectangle
A-----> area of the rectangle
we know that
The area of rectangle is equal to
\(A=x*y\\A=40\ units^{2}\)
so
\(40=x*y\) --------> equation \(1\)
\(x=6+y\) --------> equation \(2\)
Substitute equation \(2\) in equation \(1\)
\(40=[6+y]*y\\ 40=6y+y^{2} \\y^{2} +6y-40=0\)
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
\(y=4\)
Find the value of x
\(x=6+y\\ \\ x=6+4=10\ units\)
therefore
the answer is
The length of the rectangle is equal to \(10\ units\)
The width of the rectangle is equal to \(4 \ units\)
