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Kenny's weight is 6/7 times melvin's weight. what is the ratio of melvin's weight to the total weight of the two boys?

Verified Answer :

VenusRetrograde

Answer=7:13

Kenny's Weight6/7=Melvin's Weight

So, for example, if Melvin's weigh was 7...

Kenny's Weight6/7=7
divide both sides by 6/7
Kenny Weight=6

So we can say that Melvin's weight to Kenny's weight is 7:6

The boys total weights would be...
7+6=13


So Melvin's weight over the total weight of the two boys is:

7:13

calculista

Answer:

\(\frac{7}{13}\)

Step-by-step explanation:

Let

x------> Melvin's weight

y------> Kenny's weight

we know that

\(y=\frac{6}{7}x\)

\(x+y=x+\frac{6}{7}x=\frac{13}{7}x\) -----> total weight of the two boys

Find the ratio of Melvin's weight to the total weight of the two boys

\(ratio=\frac{x}{(\frac{13}{7}x)} =\frac{7}{13}\)

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