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  • 14-12-2015
  • Mathematics
Answered

find two consecutive numbers whose squares differ by 17

Verified Answer :

calculista
calculista calculista
  • 23-07-2018

Let

x---------> the first number

x+1------> the second number


we know that

\((x+1)^{2} -x^{2} =17\\ x^{2} +2x+1-x^{2} =17\\ 2x+1=17\\ 2x=16\\ x=8\)

so

\(x=8\\ x+1=9\)


therefore


the answer is

the numbers are

\(8,9\)

Answer Link

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