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AssuntaGoering608 AssuntaGoering608
  • 15-07-2014
  • Mathematics
Answered

  1. Find the exact value of sin 30 ° - sin 45 ° cos 45 ° .
A0
B1/2
C1
D2

Verified Answer :

Anonymous Anonymous
  • 15-07-2014

\(sin30^o-sin45^ocos45^o\\\\sin30^o=\frac{1}{2}\\\\sin45^o=cos45^o=\frac{\sqrt2}{2}\\\\sin30^o-sin45^ocos45^o=\frac{1}{2}-\frac{\sqrt2}{2}\cdot\frac{\sqrt2}{2}=\frac{1}{2}-\frac{2}{4}=\frac{1}{2}-\frac{1}{2}=0\\\\Answer:a.\)

Answer Link
vaibhavay
vaibhavay vaibhavay
  • 15-07-2014

sin30  1/2
sin45*cos45=1/2
=>  1/2  -  1/2 = 0

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