Verified Answer :

\(h(x)=-3x+6\\\\for\ x=0\to y=-3\cdot0+6=6\to(0;\ 6)\\\\for\ x=2\to y=-3\cdot0+6=-6+6=0\to(2;\ 0)\\\\h^{-1}(x):\\\\y=-3x+6\\3x=-y+6\ \ \ \ /:3\\x=-\frac{1}{3}y+2\\\\h^{-1}(x)=-\frac{1}{3}x+2\)

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