What are the first three terms of the sequence a1 = 3 and an = 2(an-1)^2? I thought the answer was 3,18,32 but that's not an option! help????
Answer:
3,18,648
Step-by-step explanation:
We are asked to find out the first three terms of the sequence.
Recurring formula is given as
\(a_{n} =2(a_{n-1} ^2)\)
Since I term = 3
\(a_{2} =2(a_{1})^2=2(3^2)=18\)
Applying the same rule,
third term
=\(a_{3} =2(a_{2})^2\\=2(18^2)\\=648\)
Like this we can find out any number of terms using this recursive formula