Verified Answer :

konrad509

\(f(x)=2x-6\\ y=2x-6\\ 2x=y+6\\ x=\frac{1}{2}y+3\\ f^{-1}(x)=\frac{1}{2}x+3\\ f^{-1}(2)=\frac{1}{2}\cdot2+3\\ f^{-1}(2)=1+3\\ f^{-1}(2)=4\)

Ryan2
ACalculating f⁻¹(x)

\(y=2x-6\\ \\ x=2y-6\\ \\ 2y=x+6\\ \\ y=\frac{x+6}{2}\\ \\ \boxed{f^{-1}(x)=\frac{x+6}{2}}\)

b) Calculating f⁻¹(2)

\(\boxed{\boxed{f^{-1}(2)=\frac{2+6}{2}=\frac{8}{2}=4}}\)


Related Questions