let f(x)=2x+2. solve f^-1(x) when x=4.
\(f(x)=2x+2\\ y=2x+2\\ 2x=y-2\\ x=\frac{1}{2}y-1\\ f^{-1}(x)=\frac{1}{2}x-1\\ f^{-1}(4)=\frac{1}{2}\cdot4-1\\ f^{-1}(4)=2-1\\ f^{-1}(4)=1\)
Your answer is 1. Your welcome :)
