find the missing number in 3 4/5 divide [ ] = 2 5/7
Let the unknown number be x
\(\frac{3 \frac{4}{5}}{x}=2\frac{5}{7}\)
\(3\frac{4}{5}\) can be written as \(\frac{19}{5}\)
\(2\frac{5}{7}\) can be written as \(\frac{19}{7}\)
So equation becomes
\(\frac{\frac{19}{5}}{x}=\frac{19}{7}\)
We need to get x alone, so we multiply by x on both sides
\(\frac{19}{5}=\frac{19}{7} *x\)
Now to remove 9/7 we take reciprocal and multiply it on both sides
\(\frac{19}{5} * \frac{7}{19} =\frac{19}{7}* \frac{7}{19} *x\)
\(\frac{7}{5}=x\)
The missing number is \(\frac{7}{5}\)
