a+b+c=18,b+c=10,c-b=6
c-b=6solve for cc=b+6substitute b+6 for cb+c=10b+(b+6)=102b=4b=2substitute that in to find Cc-b=6c-2=6c=8a+b+c=18a+2+8=18a+10=18a=8so a=8, b=2, c=8