find X : log2+ logx=1
\(log2+logx=1;\ D:x\in\mathbb{R^+}\\\\log(2\ \cdot\ x)=log10\iff2x=10\ \ \ /:2\\\\x=5\in D\\\\Solution:x=5.\)
\(\log2+\log x=1\\ D:x>0\\ \log2x=1\\ 10^1=2x\\ 2x=10\\ x=5\)
