Verified Answer :

Ryan2

\(P=U.i\\ \\ 60=120i\\ \\ i=0.5 \ A \\ \\ i=\frac{\Delta Q}{t}\\ \\ \Delta Q=i.t\\ \\ \Delta Q = 0.5 \ C\\ \\ Q=n.e\\ \\ n=\frac{Q}{e}\\ \\ n=\frac{0.5}{1.6*10^{-19}}=0.3125*10^{20}=3.125*10^{21} \ electrons\)

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