Answer:
the solution is the point \((1,-4)\)
Step-by-step explanation:
we have
\(4x-6y=28\)
isolate the variable x
\(4x=28+6y\)
\(x=7+1.5y\) -----> equation A
\(8x-4y=24\) -----> equation B
substitute the equation A in equation B
\(8(7+1.5y)-4y=24\)
\(56+12y-4y=24\)
\(12y-4y=24-56\)
\(8y=-32\)
\(y=-4\)
Find the value of x
\(x=7+1.5(-4)=1\)
the solution is the point \((1,-4)\)
