\(A = \frac{1}{2}bcd + bc\)
\(2(A) = 2(\frac{1}{2}bcd + bc)\)
\(2A = 2(\frac{1}{2}bcd) + 2(bc)\)
\(2A = bcd + 2bc\)
\(2A = bc(d) + bc(2)\)
\(2A = bc(d + 2)\)
\(\frac{2A}{bc} = \frac{bc(d + 2)}{bc}\)
\(\frac{2A}{bc} = d + 2\)
\(\frac{2A}{bc} - 2 = d\)
