Given the balanced equation representing a reaction:
Al2(SO4)3 +6NaOH ==> 2Al(OH)3 + 3Na2SO4
The mole ratio of NaOH to Al(OH)3 is
(1) 1:1 (2) 3:1
(3) 1:3 (4) 3:7
Al2(SO4)3 +6NaOH ==> 2Al(OH)3 + 3Na2SO4
The mole ratio of NaOH to Al(OH)3 is
(1) 1:1 (2) 3:1
(3) 1:3 (4) 3:7