Answer:
The theoretical yield of copper is 79.6281 g
Explanation:
\(CuSO_4+Zn\rightarrow ZnSO_4+Cu\)
Moles of copper sulfate = \(\frac{200.0 g}{159.609 g/mol}=1.2530 mol\)
According to reaction 1 mol of copper sulfate gives 1 mol of copper .
Then 1.2530 mol of copper sulfate will gives :
\(\frac{1}{1}\times 1.2530 mol=1.2530 mol\) of copper .
Mass of 1.2530 mol of copper :
1.2530 mol × 63.55 g/mol = 79.6281 g
The theoretical yield of copper is 79.6281 g