Answered

What is the maximum mass of methane (CH4) that can be burned if only 1.0 g of oxygen is available and how do you figure it out?

Verified Answer :

Make the reaction: \(CH_4+2O_2=CO_2+2H_2O\)
For 232=64 grams of oxygen, you can burn 216=32 grams of methane (that is, half).
So, our answer is .5g.
Other intermediate calculations are mollecular masses:
\(\mu_{CH_4}=A_C+4A_H=12+4=16 \\ mu_{O_2}=2A_O=2*16=32\)

Rohan11

Answer:

0.28 g of \(CH_4\)

Explanation:

You need a balanced equation first. \(CH_4 + 2O_2\) ⇒ \(CO_2 + 2H_2O\)

You need to find the number of moles of oxygen, which is mass divided by the Mr: 1 ÷ 32 = 1/32

Then you find the moles of methane using the mole ration oxygen to methane 2:1.  1/32 ÷ 2 = 1/64

Then you find the mass by multiplying the Mr with the number of moles:

1/64 × 18 = 0.28125 g  = 0.28 g